77x^2-92x+20=0

Solution for 77x^2-92x+20=0 equation:

77x^2-92x+20=0

a = 77; b = -92; c = +20;
Δ = b2-4ac
Δ = -922-4·77·20
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-48}{2*77}=\frac{44}{154}
=2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+48}{2*77}=\frac{140}{154}
=10/11
$